By Charles George Lamb
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Additional resources for Alternating Currents -A Text-Book for Students of Engineering
P=R ; QV QV 22 ALTERNATING CURRENTS 20 that we can adjust the scales of the different such a way that OL shall either represent the maximum pressure in the circuit or the virtual value, which is taken being a matter of convenience. It follows quantities in In this case, on a chosen scale of pressure such that OL gives the applied pressure, the lines OR and RL must also represent pressures, that is the applied pressure can be considered to have those components. Now if C be the current flowing it is evident that OL will, on the scale of pressures, be of the length C /, and and hence the pressure denoted by OR will have the value C will have the value Lp C; the former pressure that denoted by is (as before mentioned) the effective pressure and the latter the reactance pressure, the first represents that part of the applied pressure that is in phase with the current and is operative in forcing the current against the resistance, and the latter component is operative in equilibrating the pressure produced by the is Thus in Fig.
This = ^ or that the ratio of the current less condition evidently reduces to C . than the product . K> and pressure is at every instant constant, that is the curves have the same shape. It was noted on p. 15 that the sole condition that will ensure that the shape of the current curve is identical with that of the pressure one is that the circuit should contain an ohmic resistance and nothing else whatever. For in this case, as we saw, the current at any instant is exactly equal to the pressure at that instant divided by the resistance.
The vector triangle can be drawn exactly as in the last case, care being taken however to note that the current leads the pressure. r be 500, the value of TL/Fp will be 80, for it must be remembered that F has to be measured in farads let the resistance be 60 ohms, then the vector triangle will be as in Fig. 18, the current vector being drawn with a negative angle relative to the potential vector in order to show that the phase angle, whose tangent is \jFRp must be taken : SIMPLE HARMONIC CURRENTS 23 as giving the current a lead on the pressure at the terminals.